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IBM A2090-730 Exam Overview:

IBM A2090-730 Exam Syllabus Topics:

IBM Assessment: DB2 9 Family Fundamentals Sample Questions:

1. Which of the following actions will NOT cause a trigger to be fired?

A) INSERT
B) DELETE
C) ALTER
D) UPDATE

2. Given the following table definitions:
EMPLOYEE ID NAME DEPTID
01 Smith 10 02 Bossy 20 03 Peterson 20 04 Goss 30 05 Pape 40 06 Avery 50 07 O'Neal 60 08 Carter 50 DEPARTMENT ID DEPTNAME
05 Hardware 10 Kitchen 20 Shoes 30 Toys 40 Electronics 50 Automotive and the following query:
SELECT e.id, d.deptname FROM employee e, department d WHERE e.deptid = d.id AND e.id > 4
Which of the following queries will produce the same result set as the query above?

A) SELECT e.id,d.deptname FROM employee e FULL OUTER JOIN department d ON e.id = d.id WHERE e.id > 4
B) SELECT e.id,d.deptname FROM employee e INNER JOIN department d ON e.deptid = d.id WHERE e.id > 4
C) SELECT e.id,d.deptname FROM employee e LEFT OUTER JOIN department d ON e.deptid = d.id WHERE e.id > 4 UNION ALL SELECT e.id, d.deptname FROM employee e RIGHT OUTER JOIN department d ON e.deptid = d.id WHERE e.id > 4
D) SELECT e.id,d.deptname FROM employee e, department d WHERE e.id > 4

3. Given the following table definitions:
EMPLOYEES
EMPID INTEGER
NAME CHAR(20)
DEPTID CHAR(3)
SALARY DECIMAL(10,2)
COMMISSION DECIMAL(8,2)
DEPARTMENTS
DEPTNO INTEGER DEPTNAME CHAR(20)
Which of the following statements will produce a result data set that satisfies all of these conditions:
> Displays the total number of employees in each department >> Displays the corresponding department name for each department ID >> Sorted by department employee count, from greatest to least

A) SELECTdeptname, COUNT(empno) FROM departments, employees WHERE deptid = deptno GROUP BY deptname ORDER BY 2 ASC
B) SELECTdeptname, COUNT(empno) FROM departments, employees WHERE deptid = deptno GROUP BY deptname ORDER BY 2 DESC
C) SELECT *,COUNT(empno) FROM departments, employees WHERE deptid = deptno GROUP BY deptname ORDER BY 2 DESC
D) SELECTdeptname, COUNT(*) FROM departments, employees WHERE deptid = deptno GROUP BY deptname ORDER BY 2

4. A sequence was created with the DDL statement shown below:
CREATE SEQUENCE my_sequence CACHE 10 ORDER
The following statements are successfully executed in sequence through separate database connections:
CONNECTION1 - VALUES NEXT VALUE FOR my_sequence INTO :con1hvar CONNECTION2 - VALUES NEXT VALUE FOR my_sequence INTO :con2hvar CONNECTION1 - VALUES NEXT VALUE FOR my_sequence INTO :con1hvar
What is the current value of the :con1hvar host variable?

A) 30
B) 11
C) 2
D) 3

5. Given the following table definitions:
DEPARTMENT
DEPTNO CHAR(3) DEPTNAME CHAR(30) MGRNO INTEGER ADMRDEPT CHAR(3)
EMPLOYEE
EMPNO INTEGER FIRSTNAME CHAR(30) MIDINIT CHAR LASTNAME CHAR(30) WORKDEPT CHAR(3)
Which of the following statements will list every employee number and last name, along with the employee number and last name of their manager, including employees that have not been assigned to a manager?

A) SELECTe.empno, e.lastname, m.empno, m.lastname FROM employee e RIGHT OUTER JOIN department INNER JOIN employee m ON mgrno=m.empno ON e.workdept=deptno
B) SELECTe.empno, e.lastname, m.empno, m.lastname FROM employee e LEFT OUTER JOIN department INNER JOIN employee m ON mgrno=m.empno ON e.workdept=deptno
C) SELECTe.empno, e.lastname, m.empno, m.lastname FROM employee e RIGHT INNER JOIN department INNER JOIN employee m ON mgrno=m.empno ON e.workdept=deptno
D) SELECTe.empno, e.lastname, m.empno, m.lastname FROM employee e LEFT INNER JOIN department INNER JOIN employee m ON mgrno=m.empno ON e.workdept=deptno

Solutions: