ASCP ASCP-MLT Exam Overview:
| Certification Vendor: | ASCP Board of Certification (ASCP BOC) |
| Exam Name: | MEDICAL LABORATORY TECHNICIAN - MLT(ASCP) |
| Exam Number: | ASCP-MLT |
| Exam Price: | $235 USD (standard); $215 USD (reduced for eligible regions) |
| Exam Format: | Computer Adaptive Testing (CAT), Multiple-choice questions |
| Real Exam Qty: | 100 |
| Passing Score: | 400 (scale 0-999) |
| Related Certifications: | MLT(ASCPi) MLS(ASCP) PBT(ASCP) |
| Available Languages: | English |
| Exam Duration: | 150 minutes |
| Certificate Validity Period: | 3 years (renewable via CMP) |
| Recommended Training: | ASCP Recommended Reading List ASCP BOC MLT Content Guideline |
| Exam Registration: | ASCP BOC Official Application Portal Pearson VUE Testing Center Scheduling |
| Sample Questions: | ASCP ASCP-MLT Sample Questions |
| Exam Way: | Proctored computer-based testing at authorized Pearson VUE test centers |
| Pre Condition: | Associate degree or 60 semester hours from accredited institution + completion of NAACLS/ABHES-accredited MLT program OR approved education + clinical experience; multiple eligibility routes available |
| Official Syllabus URL: | https://www.ascp.org/boc/explore-credentials/view-all-credentials/MLT |
ASCP ASCP-MLT Exam Syllabus Topics:
| Section | Weight | Objectives |
|---|---|---|
| Laboratory Operations | 5-10% | - Laboratory safety and regulatory compliance - Quality control and quality assurance - Laboratory mathematics and instrumentation - Pre-analytical, analytical, and post-analytical processes |
| Hematology | 20-25% | - Routine and automated hematology procedures - White blood cell morphology and diseases - Hemostasis and coagulation testing - Red blood cell physiology and disorders |
| Microbiology | 15-20% | - Bacteriology and antimicrobial susceptibility - Mycology, parasitology, and virology - Specimen collection and culture techniques - Identification of pathogenic microorganisms |
| Urinalysis and Other Body Fluids | 5-10% | - Physical, chemical, and microscopic analysis - Urine formation and composition - Semen and amniotic fluid testing - Cerebrospinal, serous, and synovial fluids |
| Blood Banking (Immunohematology) | 15-20% | - Antibody detection and identification - Transfusion reactions and adverse events - Blood components and storage - Blood group systems and antigens - Compatibility testing |
| Clinical Chemistry | 20-25% | - Electrolytes, acid-base balance, and blood gases - Toxicology and liver/kidney function tests - Carbohydrates, lipids, proteins, and enzymes - Endocrinology and therapeutic drug monitoring |
| Immunology and Serology | 5-10% | - Immunologic testing methodologies - Autoimmune and immunodeficiency disorders - Infectious disease serology - Immune system principles and components |
ASCP MEDICAL LABORATORY TECHNICIAN - MLT(ASCP) Sample Questions:
1. Enterobius vermicularis infection occurs through swallowing ova. Pinworm infections including those caused by Enterobius vermicularis, usually occur due to a fecal-oral route of transmission. According to the CDC,
"Eggs are deposited on perianal folds. Self-infection occurs by transferring infective eggs to the mouth with hands that have scratched the perianal area. Person-to-person transmission can also occur through handling of contaminated clothes or bed linens. Enterobiasis may also be acquired through surfaces in the environment that are contaminated with pinworm eggs (e.g. , curtains, carpeting). Some small number of eggs may become airborne and inhaled. These would be swallowed and follow the same development as ingested eggs.
Following ingestion of infective eggs, the larvae hatch in the small intestine and the adults establish themselves in the colon. The time interval from ingestion of infective eggs to oviposition by the adult females is about one month. The life span of the adults is about two months. Gravid females migrate nocturnally outside the anus and oviposit while crawling on the skin of the perianal area. The larvae contained inside the eggs develop (the eggs become infective) in 4 to 6 hours under optimal conditions . Retroinfection, or the migration of newly hatched larvae from the anal skin back into the rectum, may occur but the frequency with which this happens is unknown." Enterobius vermicularis infection occurs through:
A) ingesting a segment of the adult worm
B) ingesting or inhaling ova
C) penetration of larvae through skin
D) penetration of adult through skin an resulting production of larvae
2. Personal protective equipment (PPE) should be put on in the following order:
A) gloves, mask, and gown
B) mask, gloves, and gown
C) gown, mask, and gloves
D) gloves, gown, and mask
3. The negative antigen frequencies are used in the formula below to determine the percent of type-specific units that would be compatible for the patient. Negative antigen frequencies are determined by subtracting the percent antigen frequency from 100%. The negative antigen frequency for K in this case is .91 (1.00 - .09) and the negative antigen frequency for Fya is .34 (1.00 - .66).
% compatible units available = 100 x (Neg frequency #1 x Neg frequency #2...) For this case, the calculation is:
% compatible units available = 100 x (0.91 x 0.34) = 30.94 or 31%
If the antigen frequencies for K = 0.09 and Fya = 0.66, what percent of type-specific units would be compatible for a patient with anti-K and anti-Fya?
A) 10
B) 43
C) 92
D) 100
E) 31
4. What is the first thing a phlebotomist should do in the event of an accidental needle stick?
A) leave the area so that the patient does not notice the injury
B) decontaminate the site and fill out an incident report
C) go to the employee health service and get a tetanus booster
D) check the patient's medical records
5. The normal pH of blood is 7.40. In order for most metabolic processes to take place, the pH must remain within a narrow range close to this value. The range is usually defined in adults as 7.35-7.45. If blood pH falls below 7.35, the blood becomes too acidic (acidosis). If blood rises above 7.45, the blood is too alkaline (alkalosis).
As blood pH decreases, the kidneys will retain bicarbonate (HCO3-) from the glomerular filtrate; therefore, bicarbonate is increased. However, in this case, the increased HCO3- could not compensate for the markedly elevated pCO2 (the respiratory component) and the condition that results is uncompensated respiratory acidosis.
What condition is indicated by the following blood gas results: Bicarbonate = 32 mmol/L (Normal = 22 - 26 mmol/L); pCO2 = 65 mm Hg (Normal = 35 - 45 mmHg); pH = 7.28 (normal = 7.35 - 7.45)
A) Uncompensated respiratory acidosis
B) Healthy condition
C) Uncompensated metabolic acidosis
D) Compensated metabolic acidosis
Solutions:
| Question # 1 Answer: B | Question # 2 Answer: C | Question # 3 Answer: E | Question # 4 Answer: B | Question # 5 Answer: C |

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